500x-2x^2=0

Solution for 500x-2x^2=0 equation:

500x-2x^2=0

a = -2; b = 500; c = 0;
Δ = b2-4ac
Δ = 5002-4·(-2)·0
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{250000}=500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(500)-500}{2*-2}=\frac{-1000}{-4}
=+250
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(500)+500}{2*-2}=\frac{0}{-4}
=0
$